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oracle case where 复杂sql语句

hr_user u set u.is_approve=(case when u.curr_org_id in (select t.org_id from hr_organization t start with t.org_id = 10001263 connect by prior org_id = t.org_id_parent) then ‘N‘ ELSE ‘Y‘ END); update hr_user u set u.is_approve=(case when u.curr_org_id in (select t.org_id from hr_organization t start with t.org_id = 10001263 connect by prior org_id = t.org_id_parent) then ‘N‘ ELSE ‘Y‘ END) where u.EMP_NUM=‘066001‘;

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oracle case where 复杂sql语句

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