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复杂sql分组查询 ( pivot)

Year,Months,tDays,[711], [BankIn],[iTunesHK] , [711]+[BankIn]+[iTunesHK] as total FROM ( select * from #temp) AS t PIVOT (SUM(amount) FOR [PayType] IN ( [711], [BankIn],[iTunesHK])) AS t;

效果截图如下:

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原文链接:http://www.cnblogs.com/tandaxia/p/4888623.html

复杂sql分组查询 ( pivot)

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