略微复杂的sql逻辑（从数据库逆序查找有限条记录（limit)）并按相反顺序输出

以下是我构造的sql逻辑，mark一下，亲測可行。

SELECT * FROM (SELECT *FROM group_chatmsg_v
		WHERE ((group_Id=46 AND send_user_id=28 AND receive_user_id=70)
		OR (group_Id=46 AND receive_user_id=28 AND STATUS=1))
		AND is_delete =0
		ORDER BY crtime DESC LIMIT 15) 
		AS chatMsgTable
		ORDER BY crtime ASC

略微复杂的sql逻辑（从数据库逆序查找有限条记录（limit)）并按相反顺序输出

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