原：
update stu_score_childen A set A.fScore=‘-1‘ where A.fID in (select B.fID from stu_score_childen B limit 0,50 )
更改后的
update stu_score_childen A set A.fScore=‘-1‘ where A.fID in (select C.fID from (select B.fID from stu_score_childen B limit 0,50 ) C)
绕过带有limit的select就可以了
This version of MySQL doesn't yet support 'LIMIT & IN/ALL/ANY/SOME subquery' 错误解决
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