select @num=count(distinct Salary) from EMPLOYEE if(@N<0 or @N>@num) set @N=0 RETURN ( select min(Salary) from EMPLOYEE where Salary in ( SELECT DISTINCT TOP (@N) Salary FROM EMPLOYEE order by Salary desc) ); END
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/second-highest-salary
LeetCode-SQL(一)
标签:stat 简单 用户 tco arch 组合 div table employee