MySQL实现差集(Minus)和交集(Intersect)测试报告

 drop table t1;

 drop table t2;

create table t1(id int primary key,nickname varchar(20),playNum varchar(20));

create table t2(id int primary key,nickname varchar(20),playNum varchar(20));

insert into t1 values(1,1,10);

insert into t1 values(2,2,20);

insert into t1 values(3,3,30);

insert into t2 values(1,1,10);

insert into t2 values(2,2,200);

insert into t2 values(3,33,300);

commit;

SELECT id, nickname, playNum, COUNT(*)

 FROM (SELECT id, nickname, playNum

FROM t1

UNION ALL

SELECT id, nickname, playNum

FROM t2

) a

GROUP BY id, nickname, playNum

HAVING COUNT(*) > 1

SELECT t1.id, t1.nickname, t1.playNum

 FROM t1 LEFT JOIN t2 ON t1.id = t2.id

WHERE t1.nickname != t2.nickname

OR t1.playNum != t2.playNum;