深入extjs与php参数交互的详解_PHP教程

代码如下:














代码如下:
$userName = $_POST["userName"];
$password = $_POST["password"];
$msg = "";
if($userName=="lowkey" && $password=="zq19890319") {
$msg = "登陆成功";
} else {
$msg = "登陆失败";
}
echo($msg);
?>

http://www.bkjia.com/PHPjc/327849.htmlwww.bkjia.comtruehttp://www.bkjia.com/PHPjc/327849.htmlTechArticle 代码如下:

html head titleHelloWorld/title meta http-equiv="Content-Type" content="text/html; charset=utf-8" link rel="stylesheet" type="text/css" href="../../ext-4...