是这样的,服务端返回的是一个二维数组数据,在js端 我接收到数据,但是
汉字是乱码?
出输的html是错误的,循环不出数据来??
还请高手指点一下。
js:
- JScript code
html='| " + result[i][1] + " | " + result[i][2]+ " | " + result[i][3] + " |
服务端:
- PHP code
]*>(.*)<\/table>/isU', $content,$str);
preg_match_all('/(.*)<\/tr>/isU', $str[0],$strs);
foreach ($strs[0] as $value){
//$pingyings = str_replace('__', '', $pingying);
preg_match_all('/(]*>| ]*>)(.*)(<\/td>|<\/th>|<\/div>)/isU', $value,$strs);
$zhishu[] = $strs[2];
}
for($i=1,$size=count($zhishu); $i<$size; $i++){
$zhishu[$i][0] = str_replace('', '', $zhishu[$i][0]);
//$zhishu[$i][0] = iconv('gbk', 'utf-8', $zhishu[$i][0]);
}
die(JSON($zhishu));
function arrayRecursive(&$array, $function, $apply_to_keys_also = false)
{
foreach ($array as $key => $value) {
if (is_array($value)) {
arrayRecursive($array[$key], $function, $apply_to_keys_also);
} else {
$array[$key] = $function($value);
}
if ($apply_to_keys_also && is_string($key)) {
$new_key = $function($key);
if ($new_key != $key) {
$array[$new_key] = $array[$key];
unset($array[$key]);
}
}
}
}
function JSON($array) {
arrayRecursive($array, 'urlencode', true);
$json = json_encode($array);
return urldecode($json);
}
------解决方案--------------------
你返回给 js 的是这样的字符串
[["股市名称","最新","涨跌幅%"],["道琼斯","13194.10","+0.12%"],["纳斯达克","3040.73","+0.03%"],["标普500","1394.28","-0.12%"],["法国CAC40","3564.51","+0.40%"],["日经225","10123.06","+0.72%"],["英国富时","5945.43","-0.18%"],["澳洲全股","4366.90","-0.20%"]]
因为他的格式不符合JavaScript对象符号(JSON)的规则,所以只能被 eval 解析成一维数组(js没有多维数组的概念)
接下来的事情就不必我再唠叨了吧
------解决方案--------------------
#1.php端加返回头指定编码为gb2312或者直接gbk
PHP code
------解决方案--------------------
按你的数据,只能是一维数组
你的循环错误在于
1、起点错了,数组下标从 0 开始,你却从 1
2、明明是一维数组,你却当做二维来处理,自然就文不对题了
数据是三个一组的
for (i = 0; i < size; i+=3) {
html += "" + result[i] + " " + result[i+1]+ " " + result[i+2] + " ";
}
------解决方案--------------------
用php组成2维的不就行了