PHP如何调用动态URL
RT
$id = trim($_GET['Url'],'"');
if($id<>""){
$url = 'http://www.hello-jobs.com/newsletter/'.$id.'.html';
include_once($url);
//echo $url;
测试URL是正确的，是不是我的PHP配置问题？
------解决方案--------------------
; Whether to allow include/require to open URLs (like http:// or ftp://) as files.
; http://php.com/allow-url-include
allow_url_include = on
如果包含的文件是 url 则需要打开 allow_url_include 开关
