- PHP code
include("conn.php");
function pager($rows,$page_size){
global $page,$select_from,$select_limit,$pagenav;
$page_count = ceil($rows/$page_size);
if($page <= 1 || $page == '') $page = 1;
if($page >= $page_count) $page = $page_count;
$select_limit = $page_size;
$select_from = ($page - 1) * $page_size.',';
$pre_page = ($page == 1)? 1 : $page - 1;
$next_page= ($page == $page_count)? $page_count : $page + 1 ;
$pagenav .= "第 $page/$page_count 页 共 $rows 条记录 ";
$pagenav .= "首页 ";
$pagenav .= "前一页 ";
$pagenav .= "后一页 ";
$pagenav .= "末页";
$pagenav.=" 跳到输出分页导航
$countsql="select * from manager where 0=0";
if ($_POST[chinaname]!=""){
$countsql=$countsql." and chinaname like '%$_POST[chinaname]%'";
}
if ($_POST[Tel]!=""){
$countsql=$countsql." and Tel like '%$_POST[Tel]%'";
}
$rows = mysql_num_rows(mysql_query($countsql));
$page = $_GET['page'];
pager($rows,2);
$sql = "select * from manager where 0=0";
if ($_POST[chinaname]!=""){
$sql=$sql." and chinaname like '%$_POST[chinaname]%'";
}
if ($_POST[Tel]!=""){
$sql=$sql." and Tel like '%$_POST[Tel]%'";
}
$sql=$sql." limit $select_from $select_limit";
echo $sql;
$rst = mysql_query($sql);
while($row=mysql_fetch_array($rst)){
现在的问题是当我模糊查询没有结果的时候,limit 这里显示的语句就是 limit -2,2
想现在这样的问题,应该在呢么解决呢
------解决方案--------------------
$page_count = ceil($rows/$page_size);
没有结果的时候$rows为0,得到的$page_count 也等于0,所以下面的
$select_from = (0 - 1) * 2 $select_from就得到-2了
你可以在后面加个判断 $page_count为0的时候 不加limit子句